Buford, WY – Smallest U.S. Town With 1 Resident Sold For $900,000

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    FILE  -  This Jan. 1, 2011 file photo shows Buford resident Don Sammons standing in front of the population sign in Buford, Wyo. The town advertised as the smallest in the United States has sold at auction for $900,000. (AP Photo/Wyoming Tribune Eagle, Michael Smith)Buford, WY – A Wyoming town advertised as the smallest in the United States has sold at auction for $900,000.

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    Buford is located between Cheyenne and Laramie in southeast Wyoming. An unidentified Vietnamese man placed the winning bid at auction Thursday.

    As owner of the place along Interstate 80, he will get a gas station and convenience store, a schoolhouse from 1905, a cabin, a garage, 10 acres of land, and a three-bedroom home.

    The town has had just one inhabitant, Don Sammons, who served with the U.S. Army in Vietnam in the late 1960s. He plans to retire from his unofficial title as “mayor” of the unincorporated community and write a book about his experiences in Buford.

    The town traces its origins to the 1860s and the construction of the Transcontinental Railroad.


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    9 Comments
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    Gefilte Fish
    Gefilte Fish
    12 years ago

    For that price I can buy a 1 bedroom basement apartment in BP.

    meshigener
    meshigener
    12 years ago

    Interesting why a yid didn’t buy it and start a yideshe shtetel

    sholkramer
    sholkramer
    12 years ago

    Does he get official plates for his car

    basmelech
    basmelech
    12 years ago

    I guess it doesn’t have a post office or a police dept. either. I would love to have my own town. Maybe then I wouldn’t have to pay property taxes.

    Mikerose
    Mikerose
    12 years ago

    I don’t get it -since when do towns get sold ?

    12 years ago

    He lives in the smallest town in America; I live in the largest.
    Nassau county has no cities, only 3 towns. The largest is Hempstead- has more than 59 villages and close to a million people!